The correct option is D NaBF4
In NaBF4 formation, BF3 having vacant p-orbital, i.e lewis acid, reacts with NaF i.e lewis base (because of lone pairs in F−) to form NaBF4 via dative bond. BF3 accepts the lone pair of electron from F− to form a dative bond.
BF3+NaF→NaBF4