Which of the following species has the electronic configuration $[A r] 3 d^{5}$ ?

C r

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F e^{3 +}

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M n

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V

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Solution

The correct option is B $F e^{3 +}$
$C r = 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{5}, 4 s^{1} = [A r] 3 d^{5} 4 s^{1}$
In $d$ -block, Iron $(F e)$ has the configuration $[A r] 3 d^{6} 4 s^{2}$ . If we remove 3 electrons, then it will be converted to $F e^{3 +}$ with electronic configuration $[A r] 3 d^{5}$ .
$F e^{3 +} = 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{5}, 4 s^{0} = [A r] 3 d^{5}$
$M n = 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{5}, 4 s^{2} = [A r] 3 d^{5} 4 s^{2}$
$V = 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{3}, 4 s^{2} = [A r] 3 d^{3} 4 s^{2}$
hence, correct option is (b).

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