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Magnetic Nature

Which of the ...

Question

Which of the following species is/are diamagnetic
(I) $O_{2}^{+}$ (II) $O_{2}$
(I) $O_{2}^{-}$ (II) $O_{2}^{2 -}$

O_{2}^{-}, O_{2}^{+}

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O_{2}

and

O_{2}^{2 -}

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O_{2}^{2 -}

only

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O_{2}^{+}, O_{2}^{- 2}

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Solution

The correct option is C $O_{2}^{2 -}$ only
$O_{2}$
$(σ_{1 s})^{2} (σ_{1 s}^{})^{2} (σ_{2 s})^{2} (σ_{2 s}^{})^{2} (σ_{2 p z})^{2} (π_{2 p x})^{2} = (π_{2 p y})^{2} (π_{2 p x}^{})^{1} = (π_{2 p y}^{})^{1} (σ_{2 p z}^{})^{0}$
$O_{2}^{+}$
$(σ_{1 s})^{2} (σ_{1 s}^{})^{2} (σ_{2 s})^{2} (σ_{2 s}^{})^{2} (σ_{2 p z})^{2} (π_{2 p x})^{2} = (π_{2 p y})^{2} (π_{2 p x}^{})^{1} = (π_{2 p y}^{})^{0} (σ_{2 p z}^{})^{0}$
$O_{2}^{-}$
$(σ_{1 s})^{2} (σ_{1 s}^{})^{2} (σ_{2 s})^{2} (σ_{2 s}^{})^{2} (σ_{2 p z})^{2} (π_{2 p x})^{2} = (π_{2 p y})^{2} (π_{2 p x}^{})^{2} = (π_{2 p y}^{})^{1} (σ_{2 p z}^{})^{0}$
$O_{2}^{- 2}$
$(σ_{1 s})^{2} (σ_{1 s}^{})^{2} (σ_{2 s})^{2} (σ_{2 s}^{})^{2} (σ_{2 p z})^{2} (π_{2 p x})^{2} = (π_{2 p y})^{2} (π_{2 p x}^{})^{2} = (π_{2 p y}^{})^{2} (σ_{2 p z}^{})^{0}$

$\begin{matrix} Unpaired e^{-} O_{2} = & 2 O_{2}^{+} = & 1 O_{2}^{-} = & 1 O_{2}^{2} = & 0 \end{matrix}$
The species having no unpaired electron is diamagnetic.
So, only $O_{2}^{2 -}$ is diamagnetic.

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