Which of the following species is reduced in the following (unbalanced) reaction?
$S_{2} O_{3}^{2 -} + {C l}_{2} ⟶ H {S O}_{4}^{-} + {C l}^{-}$

S_{2} O_{3}^{2} -

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C l_{2}

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None

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Both

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Solution

The correct option is C $C l_{2}$
Chlorine is reduced to chloride ion. Its oxidation number increases from 0 to -1.
$S_{2} O_{3}^{2 -}$ is oxidized to $H {S O}_{4}^{-}$

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