Question

Which of the following species/molecules has a planar geometry?

• A. $Ni(CO{)}_4$
• B. $S{F}_4$
• C. $CoC{l}_4^{2-}$
• D. $Xe{F}_4$

Answer 1

The correct option is D $Xe{F}_4$

Geometry of $Ni(CO{)}_4$ is tetrahedral

Geometry of $S{F}_4$ molecule is see-saw

Geometry of $CoC{l}_4^{-}2$ is tetrahedral

Geometry of $Xe{F}_4$ molecule is square planar

So answer is D.