Question

Which of the following statement(s) is/are true for the above two figures if each small square has side of 1 unit?

• A. Perimeter of A = Perimeter of B
• B. Area of A = Area of B
• C. Perimeter of A < Perimeter of B
• D. Area of A > Area of B

Answer 1

Answer: (B), (C)

Perimeter of A < Perimeter of B


In figure A: There are 3 squares along the length and 2 squares along the breadth.
Perimeter of figure A = length + breadth + length + breadth
= 3 + 2 + 3 + 2 = 10 cm

In figure B: There are 6 squares along the length and 1 square along the breadth.
Perimeter of figure B = length + breadth + length + breadth
= 6 + 1 + 6 + 1 = 14 cm

$\therefore$ Perimeter of A < Perimeter of B

Also, area is the total number of boxes contained by the figure,
or length × breadth

In figure A:
Number of squares = 6
Area = 6 square units
or 3 × 2 = 6 square units

In figure B:
Number of squares = 6
Area = 6 square units
or 6 × 1 = 6 square units

$\therefore$ Area of figure A = Area of figure B