    Question

# Which of the following statements are correct for a solution of H2O2 having a strength of 17g/litre ?

A

The volume strength H2O2 solution is 5.6 at 1 atmosphere pressure and 273 K temperature

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

The molarity of given H2O2 solution is 0.5 M

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

1 ml of the given H2O2 solution will give out 2.8 ml of O2 at 2 atmosphere pressure and 273 K temperature

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

The normality of given H2O2 solution is 2N.

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct options are A The volume strength H2O2 solution is 5.6 at 1 atmosphere pressure and 273 K temperature B The molarity of given H2O2 solution is 0.5 M C 1 ml of the given H2O2 solution will give out 2.8 ml of O2 at 2 atmosphere pressure and 273 K temperature Volumes strength of an H2O2 solution is the volume of O2 in litres at NTP produced by 11, of the solution. 2H2O2→2H2O+O2 68g 22.4 L at NTP ∴ Volume produced by 17g H_2O_2 (present in 1L solutoin) =22.468×17=5.6 L at NTP So the volume strength is 5.6. The volume of O2 given out at NTP by 1L of solution = 5.6L ∴ Volume of O2 given out at NTP by 1 ml of solution = 5.6 mL Converting this volume to volume at 2 atmosphere pressure and 273K temperature, we get P1V1T1=P2V2T2 or volume =5.62=2.8 ml Moles of H2O2 present in 1L solution =1734 = 0.5 moles [Mol wt = 34] ∴ Molarity of given solutoin = 0.5 M  Suggest Corrections  0      Similar questions  Related Videos   Stoichiometric Calculations
CHEMISTRY
Watch in App  Explore more