Question

Which of the following underlined atoms in oxyacids have $s{p}^3$ hybridised atoms ?

• A. $H\underset{–}{Cl}{O}_4,H_2\underset{–}{S}{O}_4,H\underset{–}{N}{O}_2$
• B. $H_2\underset{–}{S}{O}_4,H_3\underset{–}{P}{O}_4,H\underset{–}{N}{O}_3$
• C. $H\underset{–}{Cl}{O}_4,H_2\underset{–}{S}{O}_4,H_2\underset{–}{S}{O}_5$
• D. $H\underset{–}{Cl}{O}_4,H\underset{–}{N}{O}_3,H\underset{–}{Cl}{O}_3$

Answer 1

The correct option is C $H\underset{–}{Cl}{O}_4,H_2\underset{–}{S}{O}_4,H_2\underset{–}{S}{O}_5$

$H\underset{–}{Cl}{O}_4-s{p}^3$
$H_2\underset{–}{S}{O}_4-s{p}^3$
$H_2\underset{–}{S}{O}_5-s{p}^3$
$H_3\underset{–}{P}{O}_4-s{p}^3$
$H\underset{–}{N}{O}_3-s{p}^2$
$H\underset{–}{N}{O}_2-s{p}^2$