Question

Which of the following will not undergo Hell Volhard Zelinsky reaction ?

• A. $C{H}_{3}COOH$
• B. $C{H}_{3}C{H}_{2}COOH$
• C. $2,2$-Dimethyl propionic acid
• D. $2$-Methyl propionic acid

Answer 1

The correct option is C $2,2$-Dimethyl propionic acid

Only carboxylic acids having $\alpha -H$ gives Hell Volhard Zelinsky reaction. They are halogenated at the $\alpha -C$ on treatment with $B{r}_2/P$

Since, 2, 2-Dimethyl propionic acid has no $\alpha -H$, hence it will not undergo Hell Volhard Zelinsky reaction.