Which of the following will not undergo Hell- Volhard Zelinsky reaction?

HCOOH

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CH₃CH₂COOH

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CH₃CHBrCOOH

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CH₃COOH

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Solution

The correct option is A
HCOOH

Formic acid will not undergo Hell- Volhard Zelinsky reaction as it does not have α-hydrogen to be halogenated.

In Hell-Volhard Zelinsky Reaction ,Carboxylic acids having an α-hydrogen are halogenated at the alpha position on treatment with chlorine and bromine in presence red phosphorous to give α- halo carboxylic acids

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