Question

Which of the following will produce white ppt on treatment with $BaC{l}_2$ solution

• A. $\left[Cr\right(N{H}_3{)}_{4}S{O}_4]Cl$
• B. $\left[Cr\right(N{H}_3{)}_{4}C{l}_2]N{O}_2$
• C. $\left[Cr\right(N{H}_3{)}_{4}C{l}_2]S{O}_4$
• D. $Bothaandb$

Answer 1

The correct option is C $\left[Cr\right(N{H}_3{)}_{4}C{l}_2]S{O}_4$

$BaC{l}_2$ will precipitate with $\left[Cr\right(N{H}_3{)}_{4}C{l}_2]S{O}_4$ by producing $BaS{O}_4$.