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Introduction

Which of the ...

Question

Which of the following will shift the given reaction to the left side?
$P C l_{3} + C l_{2} ⇌ P C l_{5}$

A

addition of

P C l_{5}

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B

increase in pressure

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C

decrease in temperature

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D

catalyst

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Solution

The correct option is B addition of $P C l_{5}$
Given reaction $P C l_{3} + C l_{2} ⇌ P C l_{5}$ . Addition of product i.e. $P C l_{5}$ will shift the equilibrium in backward direction i.e. reaction to the left side.

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Similar questions

Q. Which of the following factor shifted the reaction,

P C l_{3} + C l_{2} ⇌ P C l_{5}

Q. Which of the following changes would decrease the dissociation of

P C l_{5}

in the reaction?

P C l_{5} ⇌ P C l_{3} + C l_{2}

Q. In the reaction

P C l_{5} ⇌ P C l_{3} + C l_{2}

the partial pressure of

P C l_{3}, C l_{2}

P C l_{5}

0.3, 0.2

0.6 a t m

respectively at equilibrium. If partial pressure of

P C l_{3}

C l_{2}

was increased twice, what will be the partial pressure of

P C l_{5}

a t m

at new equilibrium condition:

Q. In the reaction

P {C l}_{5} ⇌ P {C l}_{3} + {C l}_{2}

the partial pressure of

P {C l}_{3}, {C l}_{2}

P {C l}_{5}

are 0.3,0.2 and 0.6

a t m

respectively.If partial pressure of

P {C l}_{3}

{C l}_{2}

was increased twice,what will be the partial pressure of

P {C l}_{5}

a t m

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g),

write the expression of

K_{c} .

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