Which one among the following is the least basic :

C H_{3} N H_{2}

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N H_{3}

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C_{2} H_{5} N H_{2}

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P h N H_{2}

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Solution

The correct option is D $P h N H_{2}$
Alkyl groups are electron releasing groups having $+ I$ effect which increase electron density on $N$ of amino group and make amino group more basic. While phenyl $C_{6} H_{5}$ is electron withdrawing effect and lone pair of $N$ of amino group is in delocalization with phenyl ring make less availability of electrons and make it least basic.

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C_{3} H_{7} N H_{2}, N H_{3}, C H_{3} N H_{2}

C_{6} H_{5} N H_{2}

Arrange the following in increasing order of their basic strength:

(i) C₂H₅NH₂, C₆H₅NH₂, NH₃, C₆H₅CH₂NH₂ and (C₂H₅)₂NH

(ii) C₂H₅NH₂, (C₂H₅)₂NH, (C₂H₅)₃N, C₆H₅NH₂

(iii) CH₃NH₂, (CH₃)₂NH, (CH₃)₃N, C₆H₅NH₂, C₆H₅CH₂NH₂.

C_{6} H_{5} N H_{2}, C_{2} H_{5} N H_{2}, (C_{2} H_{5})_{2} N H, N H_{3}

C H_{3} N H_{2}, (C H_{3})_{2} N H, N H_{3}, C_{6} H_{5} N H_{2}

C_{2} H_{5} N H_{2}, N H_{3}, C_{6} H_{5} N H_{2}

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