Which one has the highest bond angle in the following?

C H_{4}

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P H_{2}^{-}

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A s H_{3}

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S b H_{3}

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Solution

The correct option is A $C H_{4}$
Correct Option- A
Reason:- $C H_{4}$ has a tetrahedral structure with $(s p)^{3}$ hybridization & thus has a bond angle of 109.5 degree whereas ${P H}_{2}^{-}$ , $A s H_{3}$ and $S b H_{3}$ has a bond angle between 90-93 degrees.

Suggest Corrections

Similar questions

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

N H_{3}, P H_{3}, A s H_{3}, S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3}, P H_{3}, A s H_{3}

S b H_{3}

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