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Avogadro's Law & Gay Lussac's Law

Which one is ...

Question

Which one is the correct relationship between molar mass $(M)$ , given mass $(m)$ and number of atoms / molecules ( $N_{A}$ ) ?

( Where, Avagadro's number = $N_{A}$ )

N = (\frac{m}{M}) \times N_{A}

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N = (\frac{M}{m}) \times N_{A}

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N = \frac{M}{(m \times N_{A})}

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None of the above

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Solution

The correct option is D $N = (\frac{m}{M}) \times N_{A}$
$M o l e s = \frac{g i v e n m a s s}{m o l a r m a s s} = \frac{m}{M}$

$N o . o f a t o m s / m o l e c u l e s, N = \frac{m}{M} \times A v o g a d r o^{'} s n u m b e r = \frac{m}{M} \times N_{A}$

Therefore option ( A ) is correct.

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Similar questions

Q. If

n (A) = m

and

n (B) = n

; then

n (A \times B) = m n

What is the value of

n (A \times B) = m n

. if

m = 6

and

n = 8

Probability of an event E, is given by P(E) $= \frac{N u m b e r o f o u t c o m e s f a v o u r a b l e t o E (m)}{N u m b e r o f a l l p o s s i b l e o u t c o m e s o f t h e e x p e r i m e n t (n)}$
Which of the following options correctly explains the relationship between m and n?

Q. Which of the following expressions is correct ? (

n

= number of moles of the gas,

N_{A}

= Avogadro constant.

m

= mass of 1 molecule of the gas.

N

= number of molecules of the gas)

Q. The number of electrons having

(n \times l \times m) = 0

N a^{+}

is :

Q. If

c {cos}^{3} θ + 3 c cos θ {sin}^{2} θ = m, c {sin}^{3} θ + 3 c {cos}^{2} θ sin θ = n

then Find

a

{(m + n)}^{a / 3} + {(m - n)}^{a / 3} = 2 c^{a / 3}

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Which one is the correct relationship between molar mass (M), given mass (m) and number of atoms / molecules (NA) ?( Where, Avagadro's number = NA)

The correct option is D N=(mM)×NAMoles=given massmolar mass=mMNo.ofatoms/molecules, N = mM×Avogadro′s number=mM×NATherefore option ( A ) is correct.

Which one is the correct relationship between molar mass $(M)$ , given mass $(m)$ and number of atoms / molecules ( $N_{A}$ ) ?

( Where, Avagadro's number = $N_{A}$ )

The correct option is D $N = (\frac{m}{M}) \times N_{A}$
$M o l e s = \frac{g i v e n m a s s}{m o l a r m a s s} = \frac{m}{M}$

$N o . o f a t o m s / m o l e c u l e s, N = \frac{m}{M} \times A v o g a d r o^{'} s n u m b e r = \frac{m}{M} \times N_{A}$

Therefore option ( A ) is correct.