Question

Which one of the above oxidation curve is wrongly presented in the given Gibbs free energy vs temperature graph ?

• A. $C\to C{O}_2$
• B. $Ti\to Ti{O}_2$
• C. $Pb\to PbO$
• D. $Mg\to MgO$

Answer 1

The correct option is B $Ti\to Ti{O}_2$

$Ti\left(s\right)+\frac{1}{2}{O}_{2\left(g\right)}\stackrel{\Delta }{\to }Ti{O}_2\left(s\right)$

By increasing temperature,

According to $\Delta G=\Delta H-T\Delta S,\Delta G$ for formation of $Ti{O}_2$ will move toward +ve value.