You visited us 1 times! Enjoying our articles? Unlock Full Access!

Continuity in an Interval

Which one of ...

Question

Which one of the discontinuous function at any point-

sin x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 / (1 / 2 x)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 / (1 + x^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $1 / (1 / 2 x)$
$1 / 1 / (2 x)$ is not defined at $x = 0$
Therefore, it is discontinuous at $x = 0$

Suggest Corrections

Similar questions

f (x) = [\frac{x^{2} + 1}{x^{2} + [| x |] + 1}]

f (x) = \frac{x + 1}{x^{2} + x - 12}

K > 0

f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} \sqrt{x^{2} - 1}, & x \leq - 1 K \frac{\sqrt{π} - \sqrt{{cos}^{- 1} x}}{x + 1}, & - 1 < x < 0 \sqrt{1 - x^{2}}, & 0 \leq x < 1 \frac{1}{sin (x - 1)} - \frac{1}{tan (x - 1)}, & x > 1 \end{matrix}

f

f

x = 1

f (x) = \frac{1}{x^{2} + x + 1}

f o g

g (x) = \frac{1}{(x - 1)}

f (x) = \frac{1}{x^{2} + x - 2}

Join BYJU'S Learning Program