Which one of the following alkenes when treated with $H C l$ yields majorly an anti-Markovnikov product?

C l - C H = C H_{2}

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H_{2} N - C H = C H_{2}

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F_{3} C - C H = C H_{2}

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C H_{3} O - C H = C H_{2}

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Solution

The correct option is C $F_{3} C - C H = C H_{2}$

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