Question

Which one of the following electyrolytes has the same value of van’t Hoff factor (i) as that of $A{l}_2(S{O}_4{)}_3$ (if all are 100% ionized)?

• A. $Al(N{O}_3{)}_3$
• B. $K_4\left[Fe\right(CN{)}_6]$
• C. $K_{2}S{O}_4$
• D. $K_3\left[Fe\right(CN{)}_6]$

Answer 1

The correct option is B

$K_4\left[Fe\right(CN{)}_6]$

$A{l}_2(S{O}_4{)}_3⟶2A{l}^{3+}+3S{O}_4^{2+},i=5$
$Al(N{O}_3{)}_3⟶A{l}^{3+}+3N{O}_3^{-},i=4$
$K_4\left[Fe\right(CN{)}_6]⟶2K^{+}S{O}_4^{2-},i=3$
$K_3\left[Fe\right(CN{)}_6]⟶3K^{+}+[Fe(CN{)}_6{]}^{4-},i=4$