Question

Which one of the following has maximum number of atoms?

• A. $1g\text{of}Ag\left(s\right)$
  $\text{Atomic mass of Ag=108}$
• B. $1g\text{of}{O}_2\left(g\right)$
  $\text{Atomic mass of O=16}$
• C. $1g\text{of}Li\left(s\right)$
  $\text{Atomic mass of Li=7}$
• D. $1g\text{of}Mg\left(s\right)$
  $\text{Atomic mass of Mg=24}$

Answer 1

The correct option is C $1g\text{of}Li\left(s\right)$

$\text{Atomic mass of Li=7}$
$\left(1\right)\text{No.of atoms of}{O}_2\left(g\right)=\frac{1}{32}\times 2\times N_A$
$\left(2\right)\text{No. of atoms of}Li\left(s\right)=\frac{1}{7}\times N_A$
$\left(3\right)\text{No. of atoms of}Ag\left(s\right)=\frac{1}{108}\times N_A$
$\left(4\right)\text{No. of atoms of}Mg\left(s\right)=\frac{1}{24}\times N_A$
$\therefore \text{1 g of Li has maximum number of atoms.}$