Question

Which one of the following has maximum number of atoms?

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Answer 1

$\left(a\right)$ Number of $\text{Mg}$ atoms = $\frac{1}{24}\times N_A$
$\left(b\right)$ Number of $\text{O}$ atoms = $\frac{1}{32}\times 2\times N_A$
$\left(c\right)$ Number of $\text{Li}$ atoms = $\frac{1}{7}\times N_A$
$\left(d\right)$ Number of $\text{Ag}$ atoms = $\frac{1}{108}\times N_A$
Hence, the correct answer is option (c).