Which one of the following ions will be colourless in an aqueous solution?

F e^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M n^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

T i^{3 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S c^{3 +}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $S c^{3 +}$
$(A)$ $F e = [A r] 3 d^{6} 4 s^{2}$

$F e^{2 +} = [A r] 3 d^{6}$

$4$ unpaired $e^{-} s ⟶$ paramagnetic.

$(B)$ $M n = [A r] 3 d^{5} 4 s^{2}$

$M n^{2 +} = [A r] 3 d^{5}$

$5$ unpaired $e^{-} s ⟶$ paramagnetic.

$(C)$ $T i = [A r] 3 d^{2} 4 s^{2}$

$T i^{3 +} = [A r] 3 d^{1}$

$1$ unpaired $e^{-} s ⟶$ paramagnetic.

$(D)$ $S c = [A r] 3 d^{1} 4 s^{2}$

$S c^{+ 3} = [A r]$

$0$ unpaired $e^{-} s ⟶$ diamagnetic.

Note: Ions which are paramagnetic show colour in an aqueous solution.

Suggest Corrections

Similar questions

T i^{3 +}, V^{3 +}

C u^{+}, S c^{3 +}

F e^{2 +}, F e^{3 +}

C o^{2} +, N i^{2 +}

Z n^{2 +}, A g^{+}

S c^{3 +}

T i^{3 +}

E^{\circ}

M n^{3 +} / M n^{2 +}

F e^{3 +} / F e^{2 +} .

S c^{3 +}

T i^{3 +}

Join BYJU'S Learning Program