Which one of the following is a correct set?

H_{2} O, s p^{3}

, angular

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B {C l}_{3}, s p^{3}

, angular

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{N H_{4}}^{+}, d s p^{2}

, square planar

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C H_{4}, d s p^{2}

, tetrahedral

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Solution

The correct option is A $H_{2} O, s p^{3}$ , angular
Molecule bp + Ip Hybridisation shape
$H_{2} O$ $2 + 2$ $s p^{3}$
angular
$B C I_{3}$ $3 + 0$ $s p^{2}$
trigonal planar
$N H_{4}^{+}$
$4 + 0$ $s p^{3}$
tetrahedral
$C H_{4}$
$4 + 0$ $s p^{3}$
tetrahedral
-

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