Which one of the following is correct about above reaction?

10 optically active compounds are formed

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8 optically active compounds are formed

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No compound of products has 2 chiral carbons

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Mixture can be separated into 8 fractions on fractional distillation

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Solution

The correct option is A 10 optically active compounds are formed
Incorrect option is (c).
Among the compounds obtained from the given reaction, 4 compounds contain 2 chiral carbons.
Possible products are shown below :

Optically active compounds are present in enantiomeric pair so no. of enantiomeric pairs are 5. Since physical property of enantiomers are identical so a pair is separated in one fraction on fractional distillation. Therefore the mixture of products can be separated into 5 + 2 = 7 fractions.

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