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Which one of the following is incorrect about above reaction?
  1. 10 optically active compounds are formed.
  2. 2 optically inactive compounds are formed.
  3. No compound of products has 2 chiral carbons.
  4. Mixture can be separated into 7 fractions on fractional distillation.


Solution

The correct option is C No compound of products has 2 chiral carbons.
Incorrect option is (c).
Among the compounds obtained from the given reaction, 4 compounds contain 2 chiral carbons.
Possible products are shown below :
Optically active compounds are present in enantiomeric pair so no. of enantiomeric pairs are 5. Since physical property of enantiomers are identical so a pair is separated in one fraction on fractional distillation. Therefore the mixture of products can be separated into 5+2=7 fractions.

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