Which one of the following is incorrect about the preparation of fluorine by Whyt law Gray's method?

fused

K H F_{2}

is used as the electrolyte

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graphite is used as anodex

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electrically heated copper cell acts as cathodex

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F_{2}

along with HF is liberated at the cathode

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Solution

The correct option is D $F_{2}$ along with HF is liberated at the cathode
Cathodic reaction in Whyt law Gray's method is as follow:
$2 H^{+} + 2 e^{-} \to H_{2}$
Thus, only $H_{2}$ is produced at the cathode.

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