The correct option is A Br2
a): Electronic Configuration of Br: [Ar]3d104s24p5. Bromine shows valency of 1 as the p-orbital is only 1 electron short to attain the inert gas configurtion.
So, for bonding p−p orbitals overlap occurs.
b): Electronic Configuration of H:1s1 (1 valence electron) and
Electronic Configuration of Br: [Ar]3d104s24p5.
So, s−p orbitals overlap.
c): Electronic Configuration of H:1s1 and Electronic Configuration of O : 1s22s22p4.
So, s−p orbitals overlap.
d): Electronic Configuration of P: 1s22s22p63s23p3
and Electronic Configuration of H: 1s1.
So, s−p orbitals overlap.