Which one of the following orders presents the correct sequence of the increasing basic nature of the given oxides?

{A l}_{2} O_{3} < M g O < N a_{2} O < K_{2} O

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M g O < K_{2} O < {A l}_{2} O_{3} < N a_{2} O

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N a_{2} O < K_{2} O < M g O < {A l}_{2} O_{3}

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K_{2} O < N a_{2} O < {A l}_{2} O_{3} < M g O

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Solution

The correct option is A ${A l}_{2} O_{3} < M g O < N a_{2} O < K_{2} O$
The basic strength of oxides increases down the group and decreases a period from left to right. Among the given element, $K$ is most metallic and $A l$ is least metallic.

So the correct order of basic nature of oxides metals is :

${A l}_{2} O_{3} < M g O < N a_{2} O < K_{2} O$

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Which of the following shows the correct order of basic nature of oxides?

C O, N a_{2} O, A l_{2} O_{3}, M g O, C O_{2}, Z n O, S O_{2}

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