Which one of the following polynomial is in standard form?

5 x^{7} - x^{1} + 2 x^{4} - x^{2}

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9 x^{8} - 4 x^{2} + 1 - x^{5}

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7 x^{3} + 9 x^{2} - x^{2} + 1 - x^{9}

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x^{6} - x^{4} - x^{2} + 1

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Solution

The correct option is D $x^{6} - x^{4} - x^{2} + 1$
The standard form for writing a polynomial is to put the term with the highest degree first, then the term with the next highest degree, and so on.
So, the last option $x^{6} - x^{4} - x^{2} + 1$ is a standard form of the polynomial.

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Similar questions

Q. Which polynomial is not in standard from?
(i)

x^{3} + x^{2} - 1 = x^{2} + x^{3}

(ii)

(x^{4} + 1) (x - x^{2})

(iii)

x^{6} + x^{3} - x + 1

Find the polynomial from the given information.

Quotient = x^{3} + 2 x

Divisor = x^{2} + \frac{1}{2} x

Remainder = 5

The degree of the polynomial obtained when $8 - 6 x + x^{2} - 7 x^{3} + x^{5}$ is subtracted from $x^{4} - 6 x^{3} + x^{2} - 3 x + 1$ is:

Q. If the median of the data

x_{1}, x_{2}, x_{3}, x_{4}, x_{5}, x_{6}, x_{7}, x_{8}

α

and

x_{1} < x_{2} < x_{3} < x_{4} < x_{5} < x_{6} < x_{7} < x_{8}

, then the median of

x_{3}, x_{4}, x_{5}, x_{6}

$I f M i s t h e m e a n o f x_{1}, x_{2}, x_{3}, x_{4}, x_{5} a n d x_{6}, p r o v e t h a t (x_{1} - M) + (x_{2} - M) + (x_{3} - M) + (x_{4} - M) + (x_{5} - M) + (x_{6} - M) = 0$

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Which one of the following polynomial is in standard form?

The correct option is D x6−x4−x2+1The standard form for writing a polynomial is to put the term with the highest degree first, then the term with the next highest degree, and so on.So, the last option x6−x4−x2+1 is a standard form of the polynomial.

The correct option is D $x^{6} - x^{4} - x^{2} + 1$
The standard form for writing a polynomial is to put the term with the highest degree first, then the term with the next highest degree, and so on.
So, the last option $x^{6} - x^{4} - x^{2} + 1$ is a standard form of the polynomial.