Which option correctly identifies the metal that will produce the most energetic electrons and their energies?

A physicist wishes to eject electrons by shining light on a metal surface. The light source emits light of wavelength of 450 nm. The table lists the only available metal and their work functions.

Lithium, 0.45 eV

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Tungsten, 1.75 eV

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Lithium, 0.15 eV

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Tungsten, 2.75 eV

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Solution

The correct option is A
Lithium, 0.45 eV

The metal having least value of work function will have the maximum kinetic energy. hence lithium will eject electrons with maximum kinetic energy.

$E_{m a x} = E_{o} - W$

Here, $E_{0} = 2.75 e V a n d W = 2.3 e V$

$\Rightarrow E_{m a x} = 2.75 e V - 2.3 e V$

$\Rightarrow E_{m a x} = 0.45 e V$

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The correct option is A Lithium, 0.45 eV The metal having least value of work function will have the maximum kinetic energy. hence lithium will eject electrons with maximum kinetic energy. Emax=Eo−W Here,E0=2.75eV and W=2.3eV ⇒Emax=2.75eV−2.3eV ⇒Emax=0.45eV