Which order is correct in spectrochemical series of ligands?

C l^{-} < F^{-} < [C_{2} O_{4}]^{2 -} < N O_{2}^{-} < C N^{-}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C N^{-} < [C_{2} O_{4}]^{2 -} < C l^{-} > N O_{2}^{-} < F^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[C_{2} O_{4}]^{2 -} < F^{-} < C l^{-} > N O_{2}^{-} < C N^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F^{-} < C l^{-} < N O_{2}^{-} < C N^{-} < [C_{2} O_{4}]^{2 -}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $C l^{-} < F^{-} < [C_{2} O_{4}]^{2 -} < N O_{2}^{-} < C N^{-}$
An experimental fact depending upon the ability of the ligand to cause crystal field splitting (i.e., strength of ligand).

Suggest Corrections

Similar questions

C N^{-}

N O_{2}

N H_{3}^{+}

F^{-}

C N^{-}, N O, O_{2}^{2 -}, O_{2}, N O_{2}, O_{2}^{-}, B_{2}, C_{2}, F_{2}^{-}

F e (C N)_{6}^{- 4} + C r_{2} O_{7}^{- 2} \to F e^{+ 3} + C_{2} O_{4}^{- 2} + N O_{2}^{-} + C r^{+ 3}

- I

- C N

N O_{2}

- N H_{2}

- F

[F e (C N)_{6}]^{- 4}, P O_{4}^{- 3}, S O_{4}^{- 2}, C l^{-}

Join BYJU'S Learning Program