Question

Which pair is correct regarding bond angle?

• A. $H_{2}O>O{F}_2$
• B. ${PCl}_3<{PBr}_3$
• C. ${NO}_2^{\bullet }>H_{2}O$
• D. All of these

Answer 1

The correct option is A $H_{2}O>O{F}_2$

A. $H_{2}O$ $⟶$ lone pair-lone pair repulsion , 2 lone pairs are present.

$O{F}_2$ $⟶$ lone pair-lone pair repulsion, 2 lone pairs are present and repulsion is also due to an electro-negativity difference.

So, $H_{2}O$ $⟶$ 104.5 degrees and $O{F}_2$ $⟶$ 101.55 degrees.

B. As the electronegativity of the surrounding atom decreases, the electron pair lies closer to the central atom and lead to an increase in repulsion and bond angle.

So, $PC{l}_3$ $⟶$ 100 degrees and $PB{r}_3$$⟶$101.5 degrees.

C. ${NO}_2^{-}$ has lone pair- bond-pair repulsion whereas $H_{2}O$ has lone pair-lone pair repulsions.