Which represents one mole?

22.4 L

H e

S T P

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16 g

O_{2}

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158 g

K M n O_{4}

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392 g

F e S O_{4} \cdot (N H_{4})_{2} S O_{4} \cdot 6 H_{2} O

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Solution

The correct options are
B $22.4 L$ $H e$ at $S T P$
C $158 g$ $K M n O_{4}$
D $392 g$ $F e S O_{4} \cdot (N H_{4})_{2} S O_{4} \cdot 6 H_{2} O$
$22.4 L$ $H e$ at $S T P$ means one mole of He.
$16 g$ $O_{2}$ means 0.5 mole $O_{2}$ .
$158 g$ $K M n O_{4}$ means one mole as molar mass is 158gm.
$392 g$ $F e S O_{4} \cdot (N H_{4})_{2} S O_{4} \cdot 6 H_{2} O$ means one mole as molar mass is 392gm.

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F e S O_{4} \cdot (N H_{4})_{2} S O_{4} \cdot 6 H_{2} O

C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O

16 g

C H_{4}

22.4 L

O_{2}

F e

F e S O_{4}

(N H_{4})_{2} S O_{4}

6 H_{2} O

The oxidation state of $F e$ in $F e S O_{4}$ . $(N H_{4})_{2} S O_{4}$ . $6 H_{2} O$ is

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