Which sample contains the largest number of atoms?

1 mg of

C_{4} H_{10}

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1 mg of

N_{2}

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1 mg of

N a

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1 mL of

H_{2} O

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Solution

The correct option is C 1 mL of $H_{2} O$
1 mg of $C_{4} H_{10} = \frac{14 N}{58} \times 10^{- 3}$ atoms,
1 mg of $N_{2} = \frac{2 N \times 10^{- 3}}{28}$ atoms,
1 mg of $N a = \frac{N \times 10^{- 3}}{23}$ atoms,
1 mL = 1 g $H_{2} O = \frac{3 N}{18}$ atoms

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Similar questions

Q. 975

m L

of a water sample contains 1

m g C a C l_{2}

and 1

m g M g C l_{2}

. Total hardness of water (in ppm) is

A water contains the following dissolved ions.
$[N a^{+}] = 56 m g / L; [C a^{2 +}] = 40 m g / L;$
$[M g^{2 +}] = 30 m g / L; [A l^{3 +}] = 3 m g / L;$
$[H C O_{3}^{-}] = 190 m g / L; [C l^{-}] = 165 m g / L;$
Water $p H$ is $7$ .
Atomic weights:
$C a = 40, M g = 24, A l = 27, H = 1, C = 12, O = 16, N a = 23, C l = 35.5$

The non-carbonate hardness of the sample in $m g / L$ as $C a C O_{3}$ is