Which set shows inert pair effect?

F e, C o, N i

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B, A l, G a

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G e, S n, P b

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H e, N e, A r

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Solution

The correct option is C $G e, S n, P b$
The inertness of s subshell electrons towards the bond formation is called inert pair effect or it can be said as the inactiveness of electrons present in outermost shell (i.e. $n s^{2}$ ) to get unpaired and involve in bond formation is called inert pair effect.
Ge, Sn, and Pb have an inert pair effect because inner s electrons have inertness due to the poor shielding capacity of the outer electrons, which brings down the oxidation state of the elements by 2.The valence p-electrons are readily available for bonding while the s-electrons are attached to the nucleus.
so, here $G e, S n, P b$ shows inert pair effect

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Similar questions

G a, A l, T l, P b, S n, G e

Match the following.

Set -I Set -II

A) Nichrome 1) Pb, Bi,Sn,Cd

B) Type metal 2) Pb,Sb,Sn

C) Woods metal 3) Cu, Al, Zn

D) Devarda's alloy 4) Fe, Ni, Cr

Stability of ions of $G e, S n, a n d P b$ will be in the order:

{S n}^{2 +} + {2 H g}^{2 +} ⟶ {H g}_{2}^{2 +} + {S n}^{4 +}

{G e}^{2 +} + {P b}^{4 +} ⟶ {p b}^{2 +} + {G e}^{4 +}

{T 1}^{+} + {G a}^{3 +} ⟶ {G a}^{+} + {T 1}^{3 +}

G e, S n

P b

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