Which statement is incorrect for $O S F_{4}$ ?

S

atom has

s p^{3} d

hybridization.

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O S F_{4}

have distorted trigonal pyramidal geometry.

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O

atom at one of the two axial positions having

S = O

bond.

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O

atom at one of the equatorial position having

S = O

bond.

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Solution

The correct option is D $O$ atom at one of the equatorial position having $S = O$ bond.
In $O S F_{4}$ , Sulphur has $s p^{3} d$ hybridisation structure. Oxygen being less electronegative occupies one of the equatorial positions.

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Similar questions

Borax is actually made of two tetrahedra and two triangular units joined together and should be written as: Na2[B4O5(OH)4]·8H2O

The correct statement/s about borax is/are:

a. Each boron atom has four B-O bonds

b. Each boron atom has three B-O bonds

c. Two boron atoms have four B-O bonds while other two have three B-O bonds

d. Each boron atom has one -OH groups

P C l_{5}

I_{3}^{-}

I_{3}^{-}

N a_{2} [B_{4} O_{5} (O H)_{4}] .8 H_{2} O

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