Which statement is true about the percent composition by mass of $C_{6} H_{12} O_{6}$ ?

Carbon is 6.7% by mass

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Oxygen is 53.3% by mass

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Hydrogen is 12% by mass

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Carbon is 72% by mass

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Carbon is 20% by mass

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Solution

The correct option is B Oxygen is 53.3% by mass
The atomic masses of C, H and O are 12 g/mol, 1 g/mol and 16 g/mol respectively.
The molar mass of glucose $C_{6} H_{12} O_{6} = 6 (12) + 12 (1) + 6 (16) = 72 + 12 + 96 =$ 180 g/mol.
The percent composition by mass of oxygen $= \frac{6 (16)}{180} \times 100 = 53.3$ %.

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A compound has the following percentage composition by mass-

Carbon-14.4%

Hydrogen-1.2%

Chlorine-85.5%

The relative molecular mass of this compound is 168.50 what ia is molecular formula?

B a S O_{4}

C O

C O_{2}

20

O_{2}

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x

x

C_{6} H_{12} O_{6}

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