Which would undergo SN1 reaction faster in the following pair and why?
CH3 |CH3−CH2−Br and CH3−C−CH3 | Br
Which would undergo SN1 reaction faster in the following pair and why?
CH3 |CH3−CH2−Br and CH3−C−CH3 | Br
Carbocations are the intermediates in the SN1 reaction. Greater the stability of the carbocations, more easily will the product be formed and hence faster will be the rate of the reaction. Because the stability of the carbocations decreases in the order: 3∘ carbocation > 2∘ carbocation > 1∘ carbocation > CH3 +. Therefore, the reactivity of alkyl halides towards SN1 reactions decreases in the same order, i.e.3∘ alkyl halides > 2∘ alkyl halides > 1∘ alkyl halides > methyl halides.
The two structures are
H2 | H3C−C−Br bromoethane
CH3 |H3C−C−CH3 2−bromo−2−methylpropane | Br
Bromoethane is a primary alkyl halide which forms a 1∘ carbocation intermediate in the SN1 reaction. The other compound is 2-bromo-2-methylpropane which is a tertiary alkyl halide which forms a tertiary carbocation intermediate in the SN1 reaction. Hence, 2-bromo-2-methylpropane undergoes an SN1 reaction faster than bromoethane.
Carbocations are the intermediates in the SN1 reaction. Greater the stability of the carbocations, more easily will the product be formed and hence faster will be the rate of the reaction. Because the stability of the carbocations decreases in the order: 3∘ carbocation > 2∘ carbocation > 1∘ carbocation > CH3 +. Therefore, the reactivity of alkyl halides towards SN1 reactions decreases in the same order, i.e.3∘ alkyl halides > 2∘ alkyl halides > 1∘ alkyl halides > methyl halides.
The two structures are
H2 | H3C−C−Br bromoethane
CH3 |H3C−C−CH3 2−bromo−2−methylpropane | Br
Bromoethane is a primary alkyl halide which forms a 1∘ carbocation intermediate in the SN1 reaction. The other compound is 2-bromo-2-methylpropane which is a tertiary alkyl halide which forms a tertiary carbocation intermediate in the SN1 reaction. Hence, 2-bromo-2-methylpropane undergoes an SN1 reaction faster than bromoethane.
