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Secondary Cells

While chargin...

Question

While charging the lead storage battery:

P b S O_{4}

anode is reduced to Pb

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P b S O_{4}

cathode is reduced to Pb

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P b S O_{4}

cathode is oxidised to Pb

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P b S O_{4}

anode is oxidised to

P b O_{2}

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Solution

The correct option is A $P b S O_{4}$ anode is reduced to Pb
Lead-acid batteries, also known as lead storage batteries, can store a lot of charge and provide high current for short periods of time.
Lead-acid batteries are capable of being recharged, which is important for their use in cars.
This type of battery can be recharged. In the charged state, each cell contains negative plates of elemental lead (Pb) and positive plates of lead(IV) oxide $(P b O_{2})$ in an electrolyte of approximately 4.2 M sulfuric acid ( $H_{2} S O_{4}$ ). The charging process is driven by the forcible removal of electrons from the positive plate and the forcible introduction of them to the negative plate by the charging source.
The charging equation is,
$2 P b S O_{4 (s)} + 2 H_{2} O_{(l)} \to P b_{(s)} + P b O_{2 (s)} + 2 H_{(a q)}^{+} + 2 H S O_{4 (a q)}^{-}$
On charging the battery the reaction is reversed and $P b S O_{4 (s)}$
is converted into Pb at anode and $P b O_{2}$ at cathode.

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Similar questions

P b + H_{2} S O_{4} \to P b S O_{4} + 2 H^{+} + 2 e^{-}

P b S + 4 H_{2} O_{2} \to P b S O_{4} + 4 H_{2} O

P b

H_{2} S O_{4}

P b S O_{4}

H

e^{-}

P b O_{2} + H_{2} S O_{4} + 2 H^{+} + 2 e^{-} \to

P b + H_{2} S O_{4} \to P b S O_{4} + 2 H^{+} + 2 e^{-}

H_{2} S O_{4}

1.294

1.139

. S u l p h u r i c a c i d o f d e n s i t y

i s

b y w e i g h t a n d t h a t o f d e n s i t y

i s

b y w e i g h t . T h e b a t t e r y h o l d

o f t h e a c i d a n d v o l u m e r e m a i n s p r a c t i c a l l y c o n s t a n t d u r i n g d i s c h a r g e . C a l c u l a t e a m p e r e - h o u r o f w h i c h t h e b a t t e r y m u s t h a v e b e e n u s e d . T h e c h a r g i n g a n d d i s c h a r g i n g r e a c t i o n s a r e :

(c h a r g i n g)

P b S O_{4} + 2 e \to P b + S O_{4}^{2 -}

P b S O_{4} + 2 H_{2} O \to P b O_{2} + S O_{4}^{2 -} + 4 H + 2 e

H_{2} 3 O_{4}

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