While jogging on a straight road, Ann covers 300 m towards east in 2 minutes 50 seconds. Then, she turned around and jogs for 1 minute covering a distance of 100 m. Calculate average speed and average velocity.

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Solution

The diagram representing the motion is as follows

From A to C:

Time taken $= 170 s + 60 s = 230 s$

Distance travelled $= 300 m + 100 m = 400 m$

Hence, $a v e r a g e s p e e d = \frac{400}{230} = 1.74 m / s$

Displacement = AC = $200 m$

So, $a v e r a g e v e l o c i t y = \frac{200}{230} = 0.869 m / s$

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While jogging on a straight road, Ann covers 300 m towards east in 2 minutes 50 seconds. Then, she turned around and jogs for 1 minute covering a distance of 100 m. Calculate average speed and average velocity.

The diagram representing the motion is as follows From A to C: Time taken =170 s+60 s=230 s Distance travelled =300 m+100 m=400 m Hence, average speed=400230=1.74 m/s Displacement = AC = 200 m So, average velocity=200230=0.869 m/s