White phosphorus reacts with chlorine and the product, hydrolyses in the presence of water. Calculate the mass of HCl obtained by the hydrolysis of the product formed by the reaction of 62 g of white phosphorus with chlorine in the presence of water.

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Solution

Reaction of white phosphorus with chlorine and hydrolysis of product formed

(1) White phosphorus $(P_{4})$ reacts with chlorine and formation of Phosphorus trichloride $(P C l_{3})$ takes place:
$P_{4} + 6 C l_{2} \to 4 P C l_{3}$

(2) In the presence of water , $P C l_{3}$ hydrolyses and gets converted to phosphorous acid $(H_{3} P O_{3})$ .
$P C l_{3} + 3 H_{2} O \to H_{3} P O_{3} + 3 H C l$

Calculating the mass of HCl obtained

Corresponding reactions are :
$P_{4} + 6 C l_{2} \to 4 P C l_{3}$ ---(i)
$P C l_{3} + 3 H_{2} O \to H_{3} P O_{3} + 3 H C l$ ---(ii)

62 grams of white phosphorus is reacted with chlorine, thus moles of white phosphorus reacted:

Number of moles $= \frac{g i v e n m a s s}{M o l a r m a s s} = \frac{62}{124} = 0.5 m o l$

Now, according to reaction(i)
1 mol of $P_{4}$ reacts to give $\to$ 4 mol of $P C l_{3}$
$∴$ 0.5 mol of $P_{4}$ will react to give $\to$ 2 mol of $P C l_{3}$

Similarly,
According to reaction (ii)
1 mol of $P C l_{3}$ reacts to give $\to$ 3 mol of HCl
$∴$ 2 mol of $P C l_{3}$ will react to give $\to 3 \times 2 =$ 6 mol of HCl.

We know,
Number of moles $= \frac{g i v e n m a s s}{M o l a r m a s s}$

$∴$ mass = number of moles $\times$ Molar mass
$= 6 m o l \times 36.5 g / m o l = 219 g$

Thus, when 62 g of white phosphorus reacts with chlorine in presence of water, 219 g of HCl is produced.

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Similar questions

Q. White phosphorous reacts with limited chlorine and the product is hydrolyzed in the presence of water. What would be the mass of HCl obtained by the hydrolysis of the product formed by the reaction of

62 g

of white phosphorus with chlorine in the presence of water?

Q. The reactions of

C l_{2}

gas with cold-dilute and hot-concentrated

N a O H

in water give sodium salts of two (different) oxoacids of chlorine,

P

and

Q,

respectively. The

C l_{2}

gas reacts with

S O_{2}

gas, in presence of charcoal, to give a product

R . R

reacts with white phosphorus to give a compound

S .

On hydrolysis,

S

gives an oxoacid of phosphorus,

T .

Which of the following produces $P C l_{3}$ ?

The reactions of $C l_{2}$ gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two different oxoacids of chlorine, P and Q, respectively. The $C l_{2}$ gas reacts with $S O_{2}$ gas, in presence of charcoal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus.

3. P and Q, respectively, are the sodium salts of

1. What do you observe when :
A) chlorine is bubbled through a solution of hydrogen
sulphide?
B) chlorine is bubbled through acidified ferrous sulphate
solution?
C) white phosphorus reacts with chlorine
D) dry chlorine is bubbled through molten sulphur
E) hydrogen and chlorine react in the presence of direct
sunlight

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