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Common Ion Effect

White precipi...

Question

White precipitate of $A g C l$ dissolves in aqueous ammonia solution due to formation of:

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Solution

AgCl is soluble in ammonia because it form complex $[A g (N H_{3})_{2}] C l$ . The formation of the complex $[A g (N H_{3})_{2}]^{+}$ ion makes it behave like ionic therefore making it soluble. If we add nitric acid it will break the coordinate bond between silver and ammonia molecule, the ammonia will react with nitric acid to form ammonium nitrate and the white precipitate of silver chloride will reappear.

$A g C l + 2 N H_{3} \to [A g (N H_{3})_{2}] C l$

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N H_{4} O H

due to the formation of :

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precipitate dissolves in

N H_{3}

due to the formation of:

Q. Gradual addition of potassium iodide solution to an aqueous solution of

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Q. The addition of

0.15 moles

N a C l

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. Find the limiting reagent and the amount of

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(A g = 108 u, C l = 35.5 u)

Q. "AgCl dissolve in ammonia solution due to the formation of complex."
Answer whether the above statement is true or false.
If true enter 1, else enter 0.

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