Why bridgehead carbon of bicyclic compound is never $s p^{2}$ or $s p$ hybridized?

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Solution

Bridgehead carbon of bi-cyclic compound is never $s p^{2}$ or $s p$ hybridized because of the high rigidity of the bi-cyclic compounds , these radicals cannot have a planar structure.

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Similar questions

s p, s p^{2} a n d s p^{3}

State whether true or false
The correct order regarding the electronegativity of hybrid orbitals of carbon is
sp > ${s p}^{2}$ > ${s p}^{3}$

^{2}

s p^{2}

s p^{3} \to s p^{2} \to s p

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