Why do we need less effort to lift a load over an inclined plane as compared to lifting the load directly ?

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Solution

For an Inclined plane,
mechanical advantage = $\frac{L}{E} = \frac{l e n g t h o f i n c l i n e d p l a n e (l)}{h e i g h t (h)}$

since l > h $⟹$ L > E
Hence we can say that less effort is required to lift a load over an individual plane because mechanical advantage increases.

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Why do we need less effort to lift a load over an inclined plane as compared to lifting the load directly ?

For an Inclined plane, mechanical advantage = LE=length of inclined plane(l)height(h)since l > h ⟹ L > EHence we can say that less effort is required to lift a load over an individual plane because mechanical advantage increases.

For an Inclined plane,
mechanical advantage = $\frac{L}{E} = \frac{l e n g t h o f i n c l i n e d p l a n e (l)}{h e i g h t (h)}$

since l > h $⟹$ L > E
Hence we can say that less effort is required to lift a load over an individual plane because mechanical advantage increases.