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Why H-C-H bon...

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Why H-C-H bond angle in CH3F is greater than that in CH3Cl

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Q. Assertion :Statement

-

1 : The bond angle in

H_{2} O

is greater than

H_{2} S

. Reason: Statement

-

-

bonding does not occur in

H_{2} S

due to low electronegativity of

S

.

Q. If true enter 1, else enter 0.
The dipole moment of

{C H}_{3} F

is greater than that of

{C H}_{3} C l

.

C H_{3} C l

has more dipole moment than

C H_{3} F

Q. Bond angle in

H_{2} O

^{\circ}

) is higher than the bond angle of

H_{2} S

^{\circ}

). The difference is due to:

Q. Consider the following statements.
I. In

S i M e_{2} C l_{2}

∠ C l - S i - C l

is smaller than

∠ M e - S i - M e

∠ M e - O - M e

M e_{2} O

is smaller than

∠ F - O - F

F_{2} O

C - C l

C H_{3} C l

is shorter than

C - C l

C F_{3} C l

C - F

C H_{3} F

is greater than

C - F

C H_{2} F_{2}

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