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SN2 Reaction Mechanism

Why in some e...

Question

Why in some element whose coordination no is 6 and ligand is NH3 hybridization is d2sp3 and sometimes sp3d2

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s p^{3} d^{2}

hybridization the same as

d^{2} s p^{3}

Q. Assertion :Statement

-

1 : Coordination isomerism occurs when both cation and anion are complex. Reason: Statement

-

2 : The complexes with coordination number 6 form octahedral complexes involving either

s p^{3} d^{2}

d^{2} s p^{3}

Q. Assertion :Transition metal ion forming octahedral complexes undergo

s p^{3} d^{2}

d^{2} s p^{3}

hybridisation. Reason: Strong field ligands force the unpaired electrons of central metal ion to pair up causing

d^{2} s p^{3}

hybridisation whereas weak field ligands do not affect electronic configuration of the metal ion undergoes in

s p^{3} d^{2}

Q. Based on VBT,

[F e C l_{6}]^{3 -}

C l^{-}

as weak ligands.

F e

s p^{3} d^{2}

hybridized (outer orbital complex) having five unpaired electrons.

[F e (C N)_{6}]^{3 -}

C N^{-}

as strong ligand.

F e

d^{2} s p^{3}

hybridized (inner orbital complex) having only one unpaired electron. Hence,

[F e C l_{6}]^{3 -}

is more paramagnetic than

[F e (C N)_{8}]^{3 -}

.
If true enter 1, else enter 0.

Structure of $I F_{4}^{+}$ and hybridization of iodine in this structure are

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