Why is sulphuric acid not used during the reaction of alcohols with $K I$ ?

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Solution

$KI and H_{2} S O_{4}$

In the presence of sulphuric add $H_{2} S O_{4}$ , $K I$ produces $H I$

The reaction is given below:

$2 K I + H_{2} S O_{4} \to 2 K H S O_{4} + 2 H l$

$Oxidising nature of H_{2} S O_{4}$

$Since H_{2} S O_{4} is an oxidising agent, it oxidizes H I to l_{2} .$

The reaction is given below:

$2 H I + H_{2} S O_{4} \to I_{2} + S O_{2} + 2 H_{2} O$

Therefore, the reaction between alcohol and $H l$ to produce alkyl iodide cannot occur.
So, sulphuric acid is not used during the reaction of alcohols with $K I .$

Instead, a non-oxidising acid such as $H_{3} P O_{4}$ is used.

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