Why is the $C - O - H$ bond angle in alcohols slightly less than the tetrahedral angle whereas the $C - O - C$ bond angle in ether is slightly greater?

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Solution

Comparing the $C - O - H & C - O - C$ bond angle

The $C - O - H$ bond angle in alcohols is slightly less than the tetrahedral angle due to the repulsion between the unshared pair of electrons or the lone pair of electrons on the oxygen atom, whereas the $C - O - C$ bond angle in ether is slightly greater than the tetrahedral angle due to the repulsive interaction between the two bulky alkyl groups.

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Q. C-O-H bond angle in alcohols is slightly less than the tetrahedral angle. Why?

The bond angle in alcohols is slightly less then the tetrahedral angle. It is due to which of the following reasons:

Q. Give reasons of the following.
(i) Phenol is more acidic than methanol.
(ii) The C-O-H bond angle in alcohols is slightly less than the tetrahedral angle

(109^{\circ} 28^{^{'}})

.
(iii)

(C H_{3})_{3} C - O - C H_{3}

on reaction with HI gives

(C H_{3})_{3} C - I a n d C H_{3} - O H

as the main products and not

(C H_{3})_{3} C - O H a n d C H_{3} - I

Assertion: Bond angle in ethers is slightly less than the tetrahedral angle.

Reason: There is a repulsion between the two bulky $(- R)$ groups.

Why in ethene angle between carbon hydrogen bonds is slightly less than angle between carbon hydrogen and carbon carbon Bond?

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Hydrides of group 16

Standard IX Chemistry

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Why is the C−O−H bond angle in alcohols slightly less than the tetrahedral angle whereas the C−O−C bond angle in ether is slightly greater?

Why is the $C - O - H$ bond angle in alcohols slightly less than the tetrahedral angle whereas the $C - O - C$ bond angle in ether is slightly greater?