Why is the $E^{0}$ value of ${M n}^{+ 3} / {M n}^{+ 2}$ couple much more positive than ${C r}^{+ 3} / {C r}^{+ 2}$ .

Due to larger third ionisation enthalpy of Mn.

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Due larger third ionisation enthalpy of Cr.

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Due to smaller third ionisation enthalpy of Mn.

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Due to lesser hydration enthalpy of Cr.

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Solution

The correct option is A Due to larger third ionisation enthalpy of Mn.
The $E^{0}$ value of $M n^{+ 3} / M n^{+ 2}$ couple is much more positive than $C r^{+ 3} / C r^{+ 2} .$ This is because $M n^{+ 3}$ ha the outer electronic configuration. of $3 d^{4}$ and $M n^{+ 2}$ has an outer electronic configuration of $3 d^{5}$ Also the outer electronic configuration of $C r^{+ 3}$ is $3 d^{3} 4 S^{0}$ (here, $t_{2} g$ orbitals are fullyfilled and hence it is more stable.
Hence The $E^{0}$ value of given couple would be more positive as its formation is more faulable due to higher stability.

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