Why is the potential inside a hollow spherical charged conductor constant and has the same value as on its surface

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Solution

Electric field intensity is zero inside the hollow spherical charged conductor. So, no work is done in moving a test charge inside the conductor and on its surface. Therefore, there is no potential difference between any two points inside or on the surface of the conductor.
$V_{A} - V_{B}$

$= - \int \to E . \to d l = 0$ $\Rightarrow$ $V_{A} = V_{B} = C o n s t a n t$

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